Write the point-slope form of the line passing through (2, -12) and parallel to y = 3x.

Solution:

Given that line passes through (2, -12) and parallel to y = 3x.

We have point slope form of equation of line as:

 (y - y₁) = m (x - x₁)

Where (x₁, y₁) is the point through which line passes.

Here, (x₁, y₁) = (2, -12) and m = slope = 3

y = 3x is of the form y = mx + c

⇒ m = 3 and c = 0 = y - intercept

Therefore, the required equation is (y + 12) = 3( x - 2)

This is the equation of line in point - slope form.

Write the point-slope form of the line passing through (2, -12) and parallel to y = 3x.

Summary:

The point-slope form of the line passing through (2, -12) and parallel to y = 3x is (y + 12) = 3( x - 2).