Which shows one way to determine the factors of x3 - 12x2 - 2x + 24 by grouping?
x(x2 - 12) + 2(x2 - 12)
x(x2 - 12) - 2(x2 - 12)
x2(x - 12) + 2(x - 12)
x2(x - 12) - 2(x - 12)
Solution:
The method of grouping for factoring polynomials is a further step to the method of finding common factors. Here we aim at finding groups from the common factors, to obtain the factors of the given polynomial expression.
It is given that
x3 - 12x2 - 2x + 24
Taking out x2 as common in the first two terms and 2 as common in the last two terms
= x2 (x - 12) - 2 (x - 12)
Therefore, the factors of x3 - 12x2 - 2x + 24 by grouping are x2 (x - 12) - 2 (x - 12).
Which shows one way to determine the factors of x3 - 12x2 - 2x + 24 by grouping?
x(x2 - 12) + 2(x2 - 12)
x(x2 - 12) - 2(x2 - 12)
x2(x - 12) + 2(x - 12)
x2(x - 12) - 2(x - 12)
Summary:
x2 (x - 12) - 2 (x - 12) shows one way to determine the factors of x3 - 12x2 - 2x + 24 by grouping.
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