Which product of prime polynomials is equivalent to 8x³ - 2x?
x(2x - 1)(2x - 1)
2x(x + 1)(x - 1)
2x2(2x + 1)(2x - 1)
2x(2x + 1)(2x - 1)

Solution:

Given polynomial is 8x³ - 2x

Take 2x as common

= 2x(4x² - 1)

= 2x((2x)² - 1)

This is in the form (a² - b²) = (a + b)(a - b)

2x(2x + 1)(2x - 1)

Therefore, the product of prime polynomials is 2x(2x + 1)(2x - 1)

Which product of prime polynomials is equivalent to 8x³ - 2x?

Summary:

The product of prime polynomials is equivalent to 8x³ - 2x is 2x(2x + 1)(2x - 1).