Which ordered pair makes both inequalities true?
y < 3x-1; y ≥ -x + 4
(4, 0) (1,2) (0, 4) (2, 1)

Solution:

The mathematical expressions in which both sides are not equal are called inequalities.

In inequality, unlike in equations, we compare two values.

The equal to sign in between is replaced by less than, greater than or not equal to sign.

It is given that

y < 3x -1 …. (1)

y > -x + 4 …. (2)

Let us take the point (4, 0)

In inequality (1)

y < 3x-1

0 < 3 (4) - 1

0 < 12 - 1

0 < 11 which is true

In inequality (2)

y ≥ - x + 4

0 ≥ -4 + 4

0 ≥ 0 …. Which is true

Therefore, the ordered pair (4, 0) makes both inequalities true.

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Which ordered pair makes both inequalities true?
y < 3x-1; y ≥ -x + 4
(4, 0) (1,2) (0, 4) (2, 1)

Summary:

The ordered pair which makes both inequalities true is (4, 0).