Which is a zero of the quadratic function f(x) = 16x² + 32x - 9?

Solution:

The given quadratic function is

f(x) = 16x² + 32x - 9

The formula of a quadratic equation ax² + bx + c = 0 is

x = [-b ± √b² - 4ac]/2a

Here a = 16, b = 32 and c = -9

Substituting the values

x = [- 32 ± √32² - 4 (16) (-9)]/ 2(16)

x = [-32 ± √1024 + 576]/ 32

By further calculation

x = [-32 ± √1600]/32

x = [-32 ± 40]/32

So we get

x = (-32 + 40)/ 32 = 8/32 = 0.25

x = (-32 - 40)/ 32 = -72/32 = -2.25

Therefore, the zero of the quadratic function is x = 0.25 and -2.25.

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Which is a zero of the quadratic function f(x) = 16x² + 32x - 9?

Summary:

The zero of the quadratic function f(x) = 16x² + 32x - 9 is x = 0.25 and -2.25.