Where does the graph of x2 - x - 2 = y cross the x-axis?
Solution:
Given, the graph x2 - x - 2 = y --- (1)
When the line crosses the x axis, y = 0
We are required to find the x-intercepts
x2 - x - 2 =0
By factoring, we get,
(x - 2)(x + 1) = 0
Solving for x, we get,
x - 2 = 0 ⇒ x = 2
x + 1 = 0 ⇒ x = -1
x = 2, -1
Putting the x value(s) in (1)
x2 - x - 2 = y
(2)2 - 2 - 2 = y
y = 0
(-1)2 - (-1) - 2 = y
y = 0
Therefore, the points are A(-1, 0) and B(2, 0).
Where does the graph of x2 - x - 2 = y cross the x-axis?
Summary:
The graph of x2 - x - 2 = y crosses the x-axis at two points A(-1, 0) and B(2, 0).
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