When rolling two 6 sided number cubes, what are the chances the sum of the roll will be 7

Solution:

When two dices are rolled together, the sample space of outcomes is

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4) , (6, 5), (6, 6)

Total number of outcomes = 36

Favorable outcomes = {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)}

We know that,

Probability of getting 7  = Number of favorable outcomes/Total number of outcomes

Substituting the values

P(Getting a sum 7) = 6/36

= 1/6

Therefore, getting the chances the sum of the roll will be 7 is 1/6.

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When rolling two 6 sided number cubes, what are the chances the sum of the roll will be 7

Summary:

When rolling two 6 sided number cubes, the chances the sum of the roll will be 7 is 1/6.