What is the vertex of g(x) = 8x² - 64x?
(4, -128), (-4, -128), (4, -16), (-4, -16)

Solution:

Given g(x) = 8x² - 64x

The vertex of a function is represented as coordinates (h,k).

In order to find vertex, we need to equate the derivative of given function to zero

g’(x) = d/dx {8x² - 64x}=0

⇒ 16(x) - 64 = 0

⇒ 16x = 64

⇒ x = 64/16 = 4

⇒ x = 4

Put x = 4 in g(x), we get

⇒ 8(4)² - 64(4)

⇒ y = 128 - 256

⇒ y = -128

Hence, the vertex is at (4, -128)

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What is the vertex of g(x) = 8x² - 64x?

Summary:

The vertex of g(x) = 8x² - 64x is at (4, -128).