What is the solution to the equation 5/(3b³ -2b² - 5) = 2/(b³ - 2)?
b = -4 and b = 0, b = -4, b = 0 and b = 4, b = 4

Solution:

Given equation is 5/(3b³ -2b² - 5) = 2/(b³ - 2)

⇒ By Cross multiplication we get,

⇒ 5b³ - 10 = 6b³ - 4b² - 10

⇒ 5b³ - 6b³ = -4b²

⇒ -b³ = -4b²

⇒ b³ - 4b² = 0

⇒ b²(b - 4) = 0

⇒ b² = 0 and b - 4 = 0

⇒ So we get b = 0 and b = 4

What is the solution to the equation 5/(3b³ -2b² - 5) = 2/(b³ - 2)?

Summary:

The solution to the equation 5/(3b³ -2b² - 5) = 2/(b³ - 2) are b = 0 and b = 4.