What is the solution of log_{2x + 3}125 = 3?

Solution:

Given equation:

log_{2x + 3}125 = 3

Apply anti-log on both sides

125 = (2x + 3)³

5³ = (2x + 3)³

If the exponents are equal, bases must be equal

5 = 2x + 3

5 - 3 = 2x

2 = 2x

x = 1

What is the solution of log_{2x + 3}125 = 3?

Summary:

The solution of log_{2x + 3}125 = 3 is x = 1