What is the product of 3a + 5 and 2a² + 4a - 2?

Solution:

Given, 3a + 5 and 2a² + 4a - 2.

We have to find the product of the given terms.

Product of 3a + 5 and 2a² + 4a - 2 = (3a + 5)(2a² + 4a - 2)

= 3a(2a²) + 3a(4a) + 3a(-2) + 5(2a²) + 5(4a) + 5(-2)

= 6a³ + 12a² - 6a + 10a² + 20a - 10

By grouping of common terms,

= 6a³ + 12a² + 10a² - 6a + 20a - 10

= 6a³ + 22a² + 14a - 10

Therefore, the required product is 6a³ + 22a² + 14a - 10.

What is the product of 3a + 5 and 2a² + 4a - 2?

Summary:

The product of 3a + 5 and 2a² + 4a - 2 is 6a³ + 22a² + 14a - 10.