What is the line containing the points (0, 4) and (3, -2)?

Solution:

Equation of line joining two points is given as a two point form as:

= (y - y\(_1\))/(y\(_2\) - y\(_1\)) = (x - x\(_1\))/(x\(_2\) - x\(_1\))

Given points are x\(_1\) = 0 and y\(_1\) = 4 and x\(_2\) = 3 and y\(_2\) = -2

The equation of line joining the given points is

(y-4)/(-2 - 4) =(x - 0)/(3 - 0)

(y-4)/(-2 - 4) =(x - 0)/(3 - 0)

⇒(y-4)/(- 6 ) = x/(3)

⇒ 3(y - 4) = x(-6)

⇒ 3y - 12 = -6x

⇒6x + 3y -12 = 0.

Dividing through out the equation by 3

⇒2x + y - 4 = 0.

The above graph represents the equation of line joining the points (0, 4) and (3, -2) which is 2x + y - 4 = 0.

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What is the line containing the points (0, 4) and (3, -2)?

Summary:

The equation of line joining the points is (0, 4) and (3, -2) is 2x + y - 4 = 0.