What is the f of x over the g of x when f(x) = 6x³ - 19x² + 16x - 4 and g(x) = x - 2?
Solution:
Given: Functions are f(x) = 6x³ - 19x² + 16x - 4 and g(x) = x - 2
Let us divide the functions f(x) and g(x).
As we know the value of f(x) / g(x) = f/g (x)
We perform the long division of polynomials given.
(6x3 - 19x2 + 16x - 4) ÷ (x - 2)
⇒ 6x² - 7x + 2
What is the f of x over the g of x when f(x) = 6x³ - 19x² + 16x - 4 and g(x) = x - 2?
Summary:
The value of f(x) over g(x) when f(x) = 6x3 - 19x2 + 16x - 4 and g(x) = x - 2 is 6x2 - 7x + 2.