What is the f of x over the g of x when f(x) = -2x³ + x² + 16x - 15 and g(x) = x + 3?

Solution:

Given f(x) = -2x³ + x² + 16x - 15 and g(x) = x + 3

Now we have to find f of x over g of x which means f(x) ÷ g(x)

So , here we have to apply the long division method were

f(x) = -2x³ + x² + 16x - 15 is the dividend and g(x) = x + 3 is the divisor

After solving by the long division method we got the remainder as 0 and the quotient as - 2x² + 7x - 5.

What is the f of x over the g of x when f(x) = -2x³ + x² + 16x - 15 and g(x) = x + 3?

Summary:

The f of x over g of x will be -2x² + 7x - 5 when f(x) = -2x³ + x² + 16x - 15 and g(x) = x + 3.