What is the equation of the line that passes through (1, 5) and (-2, 14) in slope intercept form?

Solution:

It is given that, line that passes through (1, 5) and (-2, 14)

Now we have to solve first for the slope of the line.

Given two points the slope is calculated by,

m = (y₂ - y₁) / (x₂ - x₁)

m = (14 - 5)/(-2 - 1) = -3

Use the point - slope to write the equation of the line,

y - y₂ = m(x - x₂)

Substituting the values, we get

⇒ y - 14 = - 3(x - (-2)

⇒ y = -3x + 8

Therefore, the equation of the line in slope intercept form is y = -3x + 8.

What is the equation of the line that passes through (1, 5) and (-2, 14) in slope intercept form?

Summary:

The equation of the line that passes through (1, 5) and (-2, 14) in slope intercept form is y = -3x + 8.