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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Which is the equation of the line that contains points (8, 10) and (-4, 2)?
y - 8 = 3/2 (x - 10 )
y - 10 = 3/2 (x - 8)
y - 10 = 2/3 (x - 8)
y - 8 = 2/3 (x - 10)
Solution:
The given points are (8, 10) and (-4, 2)
The equation of a line which passess through the points (x1, y1) and (x2, y2) is
y - y1 = m (x - x1)
Where m is the slope
m = (y2 - y1)/ (x2 - x1)
By substituting the values
m = (2 - 10)/ (-4 - 8)
m = -8/-12
m = 2/3
Now substituting the value of m
y - 10 = 2/3 (x - 8)
Using the multiplicative distributive property
y - 10 = 2x/3 - 16/3
y = 2x/3 - 16/3 + 10
By further calculation
y = 2x/3 - (16 - 30)/3
y = 2x/3 + 14/3
Therefore, the equation of the line is y - 10 = 2/3 (x - 8).
Which is the equation of the line that contains points (8, 10) and (-4, 2)?
Summary:
The equation of the line that contains points (8, 10) and (-4, 2) is y - 10 = 2/3 (x - 8).
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