Which is the equation of the line that contains points (8, 10) and (-4, 2)?
y - 8 = 3/2 (x - 10 ) 
y - 10 = 3/2 (x - 8) 
y - 10 = 2/3 (x - 8) 
y - 8 = 2/3 (x - 10)

Solution:

The given points are (8, 10) and (-4, 2)

The equation of a line which passess through the points (x₁, y₁) and (x₂, y₂) is

y - y₁ = m (x - x₁)

Where m is the slope

m = (y₂ - y₁)/ (x₂ - x₁)

By substituting the values

m = (2 - 10)/ (-4 - 8)

m = -8/-12

m = 2/3

Now substituting the value of m

y - 10 = 2/3 (x - 8)

Using the multiplicative distributive property

y - 10 = 2x/3 - 16/3

y = 2x/3 - 16/3 + 10

By further calculation

y = 2x/3 - (16 - 30)/3

y = 2x/3 + 14/3

Therefore, the equation of the line is y - 10 = 2/3 (x - 8).

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Which is the equation of the line that contains points (8, 10) and (-4, 2)?

Summary:

The equation of the line that contains points (8, 10) and (-4, 2) is y - 10 = 2/3 (x - 8).