What is the equation in point-slope form of the line passing through (-2, 0) and (2, 8)?
y = 2(x + 2)
y = 2(x - 2)
y = -2(x - 2)
y = -2(x + 2)

Solution:

It is given that the line passes through (-2, 0) and (2,8).

As we know, the standard equation for the point-slope form is

y - y₁ = m (x - x₁)

Where m is the slope of the line.

Now we have to find the slope using the slope formula.

Slope m = (8 - 0)/[2 - (-2)] = 2

Now, we substitute x₁ = -2 and y₁ = 0

The equation is y - 0 = 2 [x - (-2)]

⇒ y = 2x + 4

⇒ y = 2(x + 2)

Therefore, the equation in point-slope form is y = 2(x + 2).

What is the equation in point-slope form of the line passing through (-2, 0) and (2, 8)?

Summary:

The equation in point-slope form of the line passing through (-2, 0) and (2, 8) is y = 2(x + 2).