What is the completely factored form of 12xy - 9x - 8y + 6?

Solution:

Given, the polynomial is 12xy - 9x - 8y + 6

We have to find the completely factored form of the polynomial.

The given polynomial has 2 variables.

Taking common factor from the first two terms,

12xy - 9x = 3x(4y - 3)

Taking common factor from last two terms,

-8y + 6 = -2(4y - 3)

Now, 12xy - 9x - 8y + 6 = 3x(4y - 3) - 2(4y - 3)

= (3x - 2)(4y - 3)

Therefore, the completely factored form of the polynomial is (3x - 2)(4y - 3).

What is the completely factored form of 12xy - 9x - 8y + 6?

Summary:

The completely factored form of 12xy - 9x - 8y + 6 is (3x - 2)(4y - 3).