What is the center of a circle represented by the equation (x + 9)2 + (y - 6)2 = 102?
Solution:
(x + 9)2 + (y - 6)2 = 102 [Given]
Standard form of the circle is
(x - h)2 + (y - k)2 = r2 ….(1)
Where (h, k) is the center and r is the radius of the circle
So the equation can be written as
(x - (-9))2 + (y - 6)2 = 102 …. (2)
By comparing both the equations
(h, k) = (-9, 6)
r = 10
Therefore, the center of the circle is (-9, 6).
What is the center of a circle represented by the equation (x + 9)2+ (y - 6)2= 102?
Summary:
The center of a circle represented by the equation (x + 9)2 + (y - 6)2 = 102 is (-9, 6).