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What is the axis of symmetry of h(x) = 6x² - 60x + 147?
x = - 5, x = - 3, x = 3, x = 5
Solution:
The axis of symmetry is the line that divides a parabola into two identical parts.
The parabola faces upwards as the leading coefficient is positive.
The axis of symmetry of the given parabola y = 6x² - 60x + 147 is along the y-axis.
The axis of symmetry is a vertical line and is given by x = - b/ 2a
Let the polynomial be y = 6x² - 60x + 147.
Here, a = 6, b = - 60 and c = 147.
The axis of symmetry is x = - b/ 2a
Let’s solve for x.
x = - (- 60)/ 2 (6)
x = 60/ 12
x = 5
What is the axis of symmetry of h(x) = 6x² - 60x + 147?
x = - 5, x = - 3, x = 3, x = 5
Summary:
The angle of symmetry of the equation h(x) = 6x² - 60x + 147 is 5.
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