What is the axis of symmetry of h(x) = 6x² - 60x + 147?
x = - 5, x = - 3, x = 3, x = 5

Solution:

The axis of symmetry is the line that divides a parabola into two identical parts. 

The parabola faces upwards as the leading coefficient is positive.

The axis of symmetry of the given parabola y = 6x² - 60x + 147 is along the y-axis.

The axis of symmetry is a vertical line and is given by x = - b/ 2a

Let the polynomial be y = 6x² - 60x + 147.

Here, a = 6, b = - 60 and c = 147.

The axis of symmetry is x = - b/ 2a

Let’s solve for x.

x = - (- 60)/ 2 (6)

x = 60/ 12

x = 5

What is the axis of symmetry of h(x) = 6x² - 60x + 147?
x = - 5, x = - 3, x = 3, x = 5

Summary:

The angle of symmetry of the equation h(x) = 6x² - 60x + 147 is 5.