What are the zeros of the function f(x) = x² + 5x + 5 written in simplest radical form?

Solution:

We know that,

Formula to solve a quadratic equation of the form ax² + bx + c = 0 is \(x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}\)

f(x) = x² + 5x + 5 [Given]

Here a = 1, b = 5, c = 5

Substituting the values in the formula

\(\\x=\frac{-5\pm \sqrt{5^{2}-4\times 1\times 5}}{2\times 1} \\ \\x=\frac{-5\pm \sqrt{25-20}}{2} \\ \\x=\frac{-5\pm \sqrt{5}}{2}\)

Therefore, the zeros of the function f(x) = x² + 5x + 5 written in simplest radical form is \(x=\frac{-5\pm \sqrt{5}}{2}\).

What are the zeros of the function f(x) = x² + 5x + 5 written in simplest radical form?

Summary:

The zeros of the function f(x) = x² + 5x + 5 written in simplest radical form is \(x=\frac{-5\pm \sqrt{5}}{2}\).