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What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
Solution:
We know that,
Formula to solve a quadratic equation of the form ax2 + bx + c = 0 is \(x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}\)
f(x) = x2 + 5x + 5 [Given]
Here a = 1, b = 5, c = 5
Substituting the values in the formula
\(\\x=\frac{-5\pm \sqrt{5^{2}-4\times 1\times 5}}{2\times 1} \\ \\x=\frac{-5\pm \sqrt{25-20}}{2} \\ \\x=\frac{-5\pm \sqrt{5}}{2}\)
Therefore, the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form is \(x=\frac{-5\pm \sqrt{5}}{2}\).
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
Summary:
The zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form is \(x=\frac{-5\pm \sqrt{5}}{2}\).
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