What are the values of the coefficients and constant term of 0 = 4 - 7x² + x in standard form?

Solution:

The standard form of a quadratic equation is ax² + bx + c = 0 where a is the coefficient of x², b is the coefficient of x and c is the constant term.

Let us express the given equation in the standard form of quadratic equation

0 = 4 - 7x² + x

- 7x² + x + 4 = 0

or 7x² - x - 4 = 0

Coefficient of x² = 7

Coefficient of x = -1 and

Constant term = -4

What are the values of the coefficients and constant term of 0 = 4 - 7x² + x in standard form?

Summary:

The values of the coefficients and constant term of 0 = 4 - 7x² + x in standard form are 7 for x², -1 for x and -4 for constant term.