What are the roots of f(x) = x² - 48?

Solution:

Given, f(x) = x² - 48

We have to find the roots of the function.

To find the roots equate the function to zero.

x² - 48 = 0

x² = 48

Now taking square root,

x = √48

x = √16×3

So we get

x = ±4√3

x = +4√3 and -4√3

Therefore, the roots of the function are x = +4√3 and -4√3.

What are the roots of f(x) = x² - 48?

Summary:

The roots of f(x) = x² - 48 are x = +4√3 and -4√3.  To find the roots equate the function to zero.