What are the coordinates of the vertex of the function f(x) = x² + 10x - 3?

Solution:

The f(x) = x² + 10x - 3 is a quadratic equation of the form ax² + bx + c

The vertical axis of the quadratic equation is given by the expression

x = -b/2a

b = 10

a = 1

x = -10/(2×1) = -5

The y coordinate of the vertex will be obtained by substituting x = -5 in equation f(x) = x² + 10x - 3 , hence we have,

y = (-5)² + 10(-5) - 3 = 25 - 50 - 3 = -28

The vertex of the given equation f(x) = x² + 10x - 3 is (-5, -28).

What are the coordinates of the vertex of the function f(x) = x² + 10x - 3?

Summary:

The coordinates of the vertex of the given equation f(x) = x² + 10x - 3 is (-5, -28)