The Sum of Four Consecutive Odd Integers is 216. What are the Four Integers?

Let us find the four integers when the sum of those consecutive odd integers is given.

Answer: The four consecutive integers whose sum is 216 are 51, 53, 55 and 57.

Let us understand it with the help of a detailed explanation.

Explanation:

Let the first integer of the four integers be n.

Since the 4 numbers are consecutive and odd, they differ by 2.

So, the numbers will be n, (n+2), (n+4), and (n+6).

(n) + (n+2) + (n+4) + (n+6) = 216  (given)

Therefore, 4n + 12 = 216

4n = 216-12 = 204

n= 204/4 

n= 51

So, n +2 = 53

n+4 = 55

n+6 = 57

Thus, the four consecutive odd integers whose sum is 216 are 51, 53, 55, and 57.