The slope of the line tangent to the graph of y = ln(1 - x) at x = -1 is?

Solution:

Given y= ln (1 - x )

The slope of the tangent can be computed as the derivative of the given function at a point

Let y' be the derivative of the given function

y'= d/dx {In(1 - x)}

we know that d/dx (ln) = 1/x

So, y'= 1/1 - x

y' at x = -1 is y' = 1/1 - (-1) = 1/1 + 1 = 1/2

Therefore, the slope of the tangent to the given graph is 1/2.

The slope of the line tangent to the graph of y = ln(1 - x) at x = -1 is?

Summary:

The slope of the line tangent to the graph of y = ln(1 - x) at x = -1 is 1/2.