The outside diameter of a pipe is 5 and 7/32 inches. The walls of the pipe are 5/32 inches thick. What is the inside diameter?

Solution:

Outside diameter of a pipe (D)= 5 \(\dfrac{7}{32}\) inches

Thickness of the walls of the pipe (t)= 5/32 inches

The inside diameter (d) can be found by subtracting twice the wall thickness from the outside diameter.

Outside diameter = Inside Diameter+ 2(Thickness of the walls of the pipe)

D = d+ 2t

Inside Diameter = Outside diameter - 2 (Thickness of the walls of the pipe)

d = D - 2t

Substituting the values

= 5 \(\dfrac{7}{32}\) - 2 (\(\dfrac{5}{32}\))

By further calculation

= 167/32 - 10/32

So we get

= 157/32

= 4.9 inches

Therefore, the inside diameter is 4.9 inches.

---

The outside diameter of a pipe is 5 and 7/32 inches. The walls of the pipe are 5/32 inches thick. What is the inside diameter?

Summary:

The outside diameter of a pipe is 5 and 7/32 inches. The walls of the pipe are 5/32 inches thick. The inside diameter is 4.9 inches.