Suppose S and T are mutually exclusive events. Find P(S or T) if P(S) = 20% and P(T) = 22%.

Solution:

S and T are mutually exclusive events.

P(S) = 20% = 0.20

P(T) = 22% = 0.22

We know that

Probability of mutually exclusive events is

P(S or T) = P(S) + P(T)

Substituting the values

P(S or T) = 0.20 + 0.22

P(S or T) = 0.42

Therefore, the probability of (S or T) is 0.42

Suppose S and T are mutually exclusive events. Find P(S or T) if P(S) = 20% and P(T) = 22%.

Summary:

Suppose S and T are mutually exclusive events. If P(S) = 20% and P(T) = 22% P (S or T) = 0.42