Solve this equation: 80 = 3y + 2y + 4 + 1

Solution:

The given equation is

3y + 2y + 4 + 1 = 80

we get 80 = 5y + 5

⇒ 5y + 5 = 80 (By adding the like terms,)

⇒ 5y = 80 - 5 (by transposing the terms)

⇒ 5y = 75

⇒ y = 75/5

⇒ y = 15

Another similar type of problem can be: Solve this equation: 125 = 5y + 3y + 4 + 1

5y + 3y + 4 + 1 = 125

⇒ 8y + 5 = 125

⇒ 8y = 125 - 5

⇒ 8y = 120

⇒ y = 15

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Solve this equation: 80 = 3y + 2y + 4 + 1

Summary:

By solving this equation: 80 = 3y + 2y + 4 + 1 we get y = 15.