Solve the system of equations 2x + 3y = 40 and -2x + 2y = 20.

Solution:

The equations given are

2x + 3y = 40 --- (1)

-2x + 2y = 20 --- (2)

By adding both equations

⇒ 5y = 60

Dividing both sides by 5

⇒ y = 12

Substituting the value of y in equation (1)

⇒ 2x + 3(12) = 40

⇒ 2x + 36 = 40

⇒ 2x = 40 - 36

⇒ 2x = 4

Dividing both sides by 2

⇒ x = 2

Therefore, the solution to the system of equations is (2, 12).

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Solve the system of equations 2x + 3y = 40 and -2x + 2y = 20.

Summary:

The solutions to the system of equations 2x + 3y = 40 and -2x + 2y = 20 is (2, 12).