Solve the following system of equations. 2x + y = 3 and x = 2y - 1

Solution:

The equations given are

2x + y = 3 --- (1)

x = 2y - 1 --- (2)

Substituting equation (2) in (1)

⇒ 2(2y - 1) + y = 3

Using the multiplicative distributive property

⇒ 4y - 2 + y = 3

⇒ 5y = 3 + 2

⇒ 5y = 5

Dividing both sides by 5

⇒ y = 1

Substituting the value of y in equation (1)

⇒ 2x + 1 = 3

⇒ 2x = 3 - 1

⇒ 2x = 2

Dividing both sides by 2

⇒ x = 1

Therefore, the solution to the system of equations is (1, 1).

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Solve the following system of equations. 2x + y = 3 and x = 2y - 1

Summary:

The solution to the system of equations 2x + y = 3 and x = 2y - 1 is (1, 1).