Solve the differential equation cosec y dx + sec 2x dy = 0 by separation of variables.
Solution:
Given: Differential equation is cosec y dx + sec 2x dy = 0 --- (1)
By variable separable method of differential equation the given differential equation must be of the form
f(x).dx = g(y).dy or
f(x) dx ± g(y) dy = 0
Divide equation(1) by (cosec y.sec 2x)
(1/sec 2x) dx + (1/cosec y) dy = 0
cos 2x dx + sin y dy = 0
∫cos 2x dx + ∫sin y dy = C
(sin 2x / 2) - cos y = C
Where, C is an arbitrary constant.
Solve the differential equation cosec y dx + sec 2x dy = 0 by separation of variables.
Summary:
Solution of the differential equation cosec y dx + sec 2x dy = 0 by separable variables is (sin 2x / 2) - cos y = C.
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