Prove that if n is an integer and 3n + 2 is even, then n is even using a) a proof by contraposition. b) a proof by contradiction.
Solution:
We have to prove that if n is an integer and 3n + 2 is even, then n is even using
a) Proof by contraposition
A proof by contrapositive means that we will prove the opposite of the given statement.
In this case, we have to prove that when n is odd, then 3n + 2 is odd
Assume n is odd, n = 2m + 1
Where, m is an integer.
The assumed n in the given expression
3n + 2 = 3(2m+1) + 2
= 6m + 3 + 2
= 6m + 5
Rewriting the expression,
= (6m + 4) + 1
= 2(3m + 2) + 1
Now, 2(3m + 2) implies that multiplying a number (3m + 2) by 2 will always give an even number.
Adding one to the result means the final result is odd.
When n is odd, the expression 3n + 2 is odd.
b) Proof by contradiction
A proof by contradiction means we will prove that if the given statement is F, then this will lead to a contradiction.
For the given statement 3n + 2 to be F, 3n + 2 has to be even while n is odd.
Assume 3n + 2 is even and n is odd.
Substitute with the assumed n in the given expression,
3n + 2 = 3(2m + 1) + 2
= 6m + 3 + 2
= 6m + 5
Rewriting the expression,
= (6m + 4) + 1
= 2(3m + 2) + 1
Now, 2(3m + 2) implies that multiplying a number (3m + 2) by 2 will always give an even number.
Adding one to the result means the final result is odd.
The expression implies that 3m + 2 is odd which contradicts the assumption 3n + 2 is even.
Therefore,
a) proof by contraposition implies that when n is odd, the expression 3n + 2 is odd.
b) proof by contradiction implies that 3m + 2 is odd which contradicts the assumption 3n + 2 is even.
Prove that if n is an integer and 3n + 2 is even, then n is even using a) a proof by contraposition. b) a proof by contradiction.
Summary:
If n is an integer and 3n + 2 is even, then n is even using (a) a proof by contraposition implies that when n is odd, the expression 3n + 2 is odd. (b) a proof by contradiction implies that 3m + 2 is odd which contradicts the assumption 3n + 2 is even.
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