Let f(x) = x² - 3x - 7. Find f(-3).

Solution:

Given f(x) = x² - 3x - 7

It is a polynomial with degree 2

Quadratic equations are second-degree algebraic expressions and are of the form ax² + bx + c = 0.

When x = -3, then it is f(-3)

f(-3) = (-3)² - 3(-3) - 7

f(-3) = 9 + 9 - 7

f(-3) = 18 - 7 = 11

Let f(x) = x² - 3x - 7. Find f(-3).

Summary:

Let f(x) = x² - 3x - 7 then f(-3) = 11.