In how many ways can a committee of 4 be chosen from a group of 9 people?

Solution:

C=n!/(k!(n - k)!)

Where C is the number of unique combinations

n is the total number of possible choices

k is the specific number of choices

We know that,

n = 9, k = 4

Substituting it the formula

C = 9!/ (4! (9 - 4)!)

By further calculation

C = 9!/4!5!

C = 362880/(24 × 120)

So we get,

C = 362880/2880

C = 126

Therefore, in 126 ways a committee of 4 be chosen from a group of 9 people.

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In how many ways can a committee of 4 be chosen from a group of 9 people?

Summary:

In 126 ways a committee of 4 be chosen from a group of 9 people.