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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
If xy + 5ey = 5e, find the value of y'' at the point where x = 0.
Solution:
Given, xy + 5ey = 5e
Taking derivative,
d/dx (xy + 5ey) = d/dx (5e)
d/dx(xy) + d/dx (5ey) = d/dx (5e)
On solving,
(1 + xdy/dx) + 5e dy/dx = 0
On grouping,
dy/(x + 5e) dx = -1
dy/dx = -1/(x + 5e)
Now,
y’’ = d2y/dx2
d2y/dx2 = - d/dx (1/(x + 5e))
d2y/dx2 = 1/(x + 5e)2
Y’’ at x = 0 is found to be
d2y/dx2 = 1/(5e)2
d2y/dx2 = 1/25 e2
Therefore, the value of y” at x = 0 is 1/25 e2.
If xy + 5ey = 5e, find the value of y'' at the point where x = 0.
Summary:
For xy + 5ey = 5e, the value of y'' at the point where x = 0 is 1/25e2.
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