If the equation of a line is y = 3x + 2, which point cannot be on the line?
(1/3, 3), (2, 8), (0, 2), (7, 19) 

Solution:

Given: The equation of the line y = 3x+2

The condition for a point to be on a line is to satisfy its equation

(i) Let us consider (1/3, 3), substitute x = 1/3 and y = 3 in given equation

3 = 3(1/3) + 2

= 1 + 2

= 3

Hence, (1/3, 3) lies on the line

(ii) Let us consider (2, 8) and substitute x = 2 and y = 8 in given equation

8 = 3(2) + 2

= 6 + 2

= 8

Hence, (2, 8) lies on the line

(iii) Let us consider (0, 2) and substitute x = 0 and y = 2 in given equation

2 = 3(0) + 2 = 2

Hence, (0, 2) lies on the line

(iv) Let us consider (7, 19) and substitute x = 7 and y = 19 in given equation

19 = 3(7) + 2

= 21+ 2

= 23 ≠ 19

hence, (7,19) doesn’t lie on the line

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If the equation of a line is y = 3x + 2, which point cannot be on the line?

Summary:

If the equation of a line is y = 3x + 2 then point (7, 19) cannot be on the line.