If p(x) = x³ - x² + 3x + 4, then find the value of p (1) and p (- 2)

To solve this equation, we will substitute the values of x and simplify.

Answer: If p(x) = x³ - x² + 3x + 4, then, the value of p (1) = 7 and p (- 2 ) = - 14. 

Here are the steps.

Explanation:

Given, p(x) = x³ - x² + 3x + 4

For p(1) we substitute x = 1 in p(x)

= (1)³ - (1)² + 3(1) + 4

= 1 - 1 + 3 + 4

= 7

substituting x = -2 in p(x)  we have

(-2) = (-2)³ - (-2)² + 3 (-2) + 4

=  - 8 - (+4) - 6 + 4

= - 8 - 4 - 6 + 4

= - 14

Thus, if p(x) = x³ - x² + 3x + 4, then, the value of p (1) = 7 and p (-2) = - 14.