If p(x) = x² - 1 and q(x) = 5(x - 1), which expression is equivalent to (p - q)(x)?
5(x - 1) - x² - 1 
(5x - 1) - (x² - 1)
(x² - 1) - 5(x - 1)
(x² - 1) - 5x - 1 

Solution:

It is given that

p(x) = x² - 1

q(x) = 5(x - 1)

We have to find (p - q)(x)

We know that

(p - q)(x) = p(x) - q(x)

Substituting the values

= (x² - 1) - 5(x - 1)

Therefore, the expression equivalent to (p - q)(x) is (x² - 1) - 5(x - 1).

Example:

If p(x) = 2x² - 1 and q(x) = 3(x - 1), which expression is equivalent to (p - q)(x)? 

Solution:

It is given that

p(x) = 2x² - 1

q(x) = 3(x - 1)

We have to find (p - q)(x)

We know that

(p - q)(x) = p(x) - q(x)

Substituting the values

= (2x² - 1) - 3(x - 1)

Therefore, the expression equivalent to (p - q)(x) is (2x² - 1) - 3(x - 1).

---

If p(x) = x² - 1 and q(x) = 5(x - 1), which expression is equivalent to (p - q)(x)? 

Summary:

If p(x) = x² - 1 and q(x) = 5(x - 1), the expression which is equivalent to (p - q)(x) is (x² - 1) - 5(x - 1).