If f(x) = 2x + 1 and g(x) = (x - 1)/2 , then f(g(x))

Solution:

Given, f(x) = 2x + 1

g(x) = (x - 1)/2

We have to find f(g(x))

f(g(x)) = f((x - 1)/2)

= 2[(x - 1)/2] + 1

= 2x/2 - 2/2 + 1

= x - 1 + 1

= x

Therefore, f(g(x)) = x.

Example:  If f(x) = 3x + 1 and g(x) = x - 1 , then f(g(x)) =

Solution:

Given, f(x) = 3x + 1

g(x) = x - 1

We have to find f(g(x))

f(g(x)) = f((x - 1)

= 3[(x - 1)] + 1

= 3x - 3 + 1

= 3x - 2

Therefore, f(g(x)) = 3x - 2.

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If f(x) = 2x + 1 and g(x) = (x - 1)/2 , then f(g(x)) 

Summary:

If f(x) = 2x + 1 and g(x) = (x - 1)/2, then f(g(x)) is x.