If f(x) = 16x - 30 and g(x) = 14x - 6, for which value of x does (f - g)(x) = 0?
-18, -12, 12, 18

Solution:

Given: Functions are f(x) = 16x - 30 and g(x) = 14x - 6

To find: (f - g)(x)

As we know that f(x) - g(x) = (f - g) (x)

(f - g)(x) = (16x - 30) - (14x - 6)

(f - g)(x) = 2x - 24

When (f - g)(x) = 0, 2x - 24 = 0

By solving for x, we get

2x = 24

⇒ x = 12

If f(x) = 16x - 30 and g(x) = 14x - 6, for which value of x does (f - g)(x) = 0?
- 18, - 12, 12, 18

Summary:

The value of x = 12 for which (f - g)(x) = 0 for f(x) = 16x - 30 and g(x) = 14x - 6.