If f(x) = 1 - x, which value is equivalent to |f(i)|?
Solution:
Given f(x) = 1 - x
In order to get the value of |f(i)|, we need to put x = i
f(i) = 1 - i
This is imaginary pair function in the form a +ib
The modulus of an imaginary function can be given as√(a2 + b2)
Here, a = 1 and b = -1
|f(lui)| = √(12 + (-1)2)
|f(i)| = √(1 + 1)
|f(i)| = √2
Therefore, the value of |f(i)| is √2
If f(x) = 1 - x, which value is equivalent to |f(i)|?
Summary:
If f(x) = 1 - x, then the value of |f(i)| is √2.
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