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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
If cos x = sin(20 + x)° and 0° < x < 90°, then the value of x is
Solution:
Given that, cos x = sin(20 + x)° and 0° < x < 90°
Clearly, it is given that x lies in 1st Quadrant
We know that sine and cosine are co-functions, which means cos x = sin (90° - x) if x lies in Q1
So, we can replace cos x with sin(90 - x) in the given equation
⇒ cos x = sin(20 + x)°
⇒ sin(90 - x) = sin(20 + x)
Apply sin-1 on both sides, we get sin-1 and sin get cancelled
90° - x = 20° + x
90° - 20° = x + x
70° = 2x
x = 35°
Therefore, the value of x is 35°.
If cos x = sin(20 + x)° and 0° < x < 90°, then the value of x is
Summary:
If cos x = sin(20 + x)° and 0° < x < 90°, then the value of x is 35°.
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