Identify this conic section x² - 4x + y² - 4y + 4 = 12.
Line, circle, ellipse, parabola, hyperbola

Solution:

The equation of the conic section is

x² - 4x + y² - 4y + 4 = 12

Let us find the standard form

x² - 4x + y² - 4y + 4 = 12

By adding 4 on both sides and separating the terms

(x² - 4x + 4) + (y² - 4y + 4) = 12 + 4

(x - 2)² + (y - 2)² = 16

(x - 2)² + (y - 2)² = 4²

Therefore, the conic section given is a circle with centre (2, 2) and radius 4.

Identify this conic section x² - 4x + y² - 4y + 4 = 12.

Summary:

The conic section x² - 4x + y² - 4y + 4 = 12 is a circle with centre (2, 2) and radius 4.