How to differentiate log(1 + x + x²) function?

Differentiation is one of the most important concepts in calculus. It is the reverse of integration. The slopes of various curves at different points can be found out using differentiation.

Answer: The derivative of log(1 + x + x²) function is (2x + 1) / (1 + x + x²).

Let's understand the solution in detail.

Explanation:

We know that the derivative of log |x| is 1/x.

Hence, if we have to differentiate log(1 + x + x²), we use the chain rule.

Hence, derivative of log(1 + x + x²) = d { log(1 + x + x²) }/dx . d (1 + x + x²)/dx

Therefore, derivative of log(1 + x + x²) = 1 / (1 + x + x²) . (0 + 1 + 2x).

Hence, The derivative of log(1 + x + x²) function is (2x + 1) / (1 + x + x²).