

How can you find the maximal volume of a rectangular box inscribed in a sphere?
Solution:
To find the maximum volume of the rectangle inscribed in a sphere, we begin with the general equation of the sphere of radius r in terms of coordinates x, y and z, which is
x2 + y2 + z2 = r2 --- (1)
The volume of the rectangular box inside the sphere in terms of coordinates x, y, and z shall be
Vb = 2x.2y.2z = 8xyz --- (2)
To find the maximal volume of the box one has to differentiate partially equation (2) w.r.t the variables in which volume is expressed.
One shall substitute the value of z in terms of x and y in equation 2 to simplify the maximization process. So we get
z = √r2 - x2 - y2
Therefore the volume of the rectangular box can be expressed as:
Vb = 8.x.y. √r2 - x2 - y2 --- (3)
Partially differentiating the above w.r.t. x
∂Vb∂x = ∂8.x.y.√r2−x2−y2∂x
∂Vb∂x = √r2−x2−y2∂(8xy)∂x+8xy∂√r2−x2−y2∂x
= √r2 - x2 - y2 × (8y) + (8xy)(-2x)(1/2)(r2 - x2 - y2)-1/2
= 8y × √r2 - x2 - y2 - 8x2y/(√r2 - x2 - y2)
= 8y(r2 - x2 - y2) - 8x2y/(√r2 - x2 - y2)
= 8y(r2 - x2 - y2 - x2)/(√r2 - x2 - y2)
= 8y((r2 -2x2 - y2)/(√r2 - x2 - y2) --- (4)
Similarly differentiating equation (3) partially w.r.t. y we get,
∂Vb∂x = 8x((r2 - x2 - 2y2)/(√r2 - x2 - y2) --- (5)
Equations (4) and (5) are partial derivatives and have to be equated to zero to maximize the volume of the rectangular box.
Since the denominator of both equations (4) & (5) cannot be zero and x and y cannot be zero the only alternative left is:
(r2 -2x2 - y2) = 0 ⇒ 2x2 + y2 = r2 --- (6)
(r2 - x2 - 2y2) = 0 ⇒ x2 + 2y2 = r2 --- (7)
Multiplying (7) by 2 and subtracting from (6) we get,
-3y2 = -r2 ⇒ y = r/√3 --- (8)
Similarly multiplying (6) by 2 and subtracting (7) from it) we get,
3x2 = r2 ⇒ x = r/√3 --- (9)
Substituting (8) and (9) in the volume equation (3) we have,
Vb = 8(r/√3)(r/√3)√(r2 - (r/√3)2 - ( r/√3)2
Vb = 8(r2/3)√(r2 - r2/3 - r2/3)
= (8/3)(r2)√3r2 - r2 - r2)/3
= (8/3)(r2)√r2/3
= 8r3/3√3
Hence, the maximal volume of a rectangular box inside the sphere is 8r3/3√3.
How can you find the maximal volume of a rectangular box inscribed in a sphere?
Summary:
The maximal volume of the rectangle inside the sphere of radius r and that volume is 8r3/3√3.
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