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How can one half x - 5 = one third x + 6 be set up as a system of equations?
Solution:
One half x - 5 = one third x + 6 [Given]
It can be mathematically written as
1/2 x - 5 = 1/3 x + 6
First rewrite it into two separate equations
y = 1/2 x - 5 … (1)
y = 1/3 x + 6 … (2)
Both the equations can be written as
equation (1):y = (x - 10)/2
2y = x - 10
2y - x = - 10
equation (2):y = (x + 18)/3
3y = x + 18
3y - x = 18
Therefore, one half x - 5 = one third x + 6 can be set up as a system of equations as 2y - x = -10 and 3y - x = 18.
How can one half x - 5 = one third x + 6 be set up as a system of equations?
Summary:
One half x - 5 = one third x + 6 can be set up as a system of equations as 2y - x = -10 and 3y - x = 18.
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