Given the function f(x) = 3(x + 2) - 4, solve for the inverse function when x = 2.

Solution:

Given: Function f(x) = 3(x + 2) - 4

Consider f(x) as y

y = 3(x + 2) - 4

Replace x by y

x = 3(y + 2) - 4

It can be written as

x + 4 = 3(y + 2)

Divide both sides by 3

(x + 4)/3 = y + 2

(x + 4)/3 - 2 = y

So f^-1(x) = (x + 4)/3 - 2

Let us solve by substituting x as 2

f^-1(2) = (2 + 4)/3 - 2

By further calculation

f^-1(2) = 6/3 - 2

f^-1(2) = 2 - 2

f^-1(2) = 0

Therefore, the inverse function when x = 2 is 0.

Given the function f(x) = 3(x + 2) - 4, solve for the inverse function when x = 2.

Summary:

Given the function f(x) = 3(x + 2) - 4, the inverse function when x = 2 is 0.