Find the probability of getting 53 Sundays in a non-leap year: (1) 2/7 (2) 1/7 (3) 1/5 (4) 1/9

The probability of an event is the ratio of a number of favorable outcomes to the total number of favorable outcomes of the event and lies between 0 and 1.

Answer: The probability of getting 53 Sundays in a non-leap year is 1/7

Let's find the probability of getting 53 Sundays in a non-leap year.

Explanation:

A non-leap year has 365 days.

In 365 days, there are 52 weeks and 1 day

In 52 weeks, the number of Sundays will be 52.

1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday

We can have any one of these days out of 7 days

Hence, out of these 7 outcomes, the favorable outcome is 1

Therefore, Probability of getting 53 Sundays in a non-leap year = 1 / 7

Thus, Option (2) the probability of getting 53 Sundays in a non-leap year is 1/7