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Find the point on the line y = 2x + 3 that is closest to the origin.
Solution:
Given, equation of the line is y = 2x + 3 ---------(1)
Closest point from origin will be the perpendicular distance from origin to the line.
We need to find an equation of the perpendicular from (0,0) on y = 2x + 3.
The equation is in slope-intercept form i.e. y = mx + c
Slope, m = 2
Slope of the perpendicular = - (1/m) = -1/2
Equation of the perpendicular is found by (y - y1) = m (x - x1)
y - 0 = (-1/2) (x - 0)
y = (-1/2)x
2y + x = 0 ----------------(2)
Solving (1) and (2), we get,
5y = 3
y = 3/5
x + 2(3/5) = 0
x = -6/5
x = -6/5 and y = 3/5
Therefore, the point on the line is (-6/5, 3/5).
Find the point on the line y = 2x + 3 that is closest to the origin.
Summary:
The point on the line y = 2x + 3 that is closest to the origin is (-6/5 , 3/5).
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